(2a+1)(2a-1)(2a-10)=8a^2-42a+10

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Solution for (2a+1)(2a-1)(2a-10)=8a^2-42a+10 equation: 



(2a+1)(2a-1)(2a-10)=8a^2-42a+10

We move all terms to the left:

(2a+1)(2a-1)(2a-10)-(8a^2-42a+10)=0

We get rid of parentheses

-8a^2+(2a+1)(2a-1)(2a-10)+42a-10=0

We multiply parentheses ..

-8a^2+(+4a^2-2a+2a-1)(2a-10)+42a-10=0

We move all terms containing a to the left, all other terms to the right

-8a^2+(+4a^2-2a+2a-1)(2a-10)+42a=10

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